3.253 \(\int \frac {1}{\sqrt {-1-x^2} \sqrt {2-x^2}} \, dx\)

Optimal. Leaf size=31 \[ \frac {\sqrt {x^2+1} \operatorname {EllipticF}\left (\sin ^{-1}\left (\frac {x}{\sqrt {2}}\right ),-2\right )}{\sqrt {-x^2-1}} \]

[Out]

EllipticF(1/2*x*2^(1/2),I*2^(1/2))*(x^2+1)^(1/2)/(-x^2-1)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {421, 419} \[ \frac {\sqrt {x^2+1} F\left (\left .\sin ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right |-2\right )}{\sqrt {-x^2-1}} \]

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[-1 - x^2]*Sqrt[2 - x^2]),x]

[Out]

(Sqrt[1 + x^2]*EllipticF[ArcSin[x/Sqrt[2]], -2])/Sqrt[-1 - x^2]

Rule 419

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1*EllipticF[ArcSin[Rt[-(d/c),
2]*x], (b*c)/(a*d)])/(Sqrt[a]*Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] &
& GtQ[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-(b/a), -(d/c)])

Rule 421

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Dist[Sqrt[1 + (d*x^2)/c]/Sqrt[c + d*
x^2], Int[1/(Sqrt[a + b*x^2]*Sqrt[1 + (d*x^2)/c]), x], x] /; FreeQ[{a, b, c, d}, x] &&  !GtQ[c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {-1-x^2} \sqrt {2-x^2}} \, dx &=\frac {\sqrt {1+x^2} \int \frac {1}{\sqrt {2-x^2} \sqrt {1+x^2}} \, dx}{\sqrt {-1-x^2}}\\ &=\frac {\sqrt {1+x^2} F\left (\left .\sin ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right |-2\right )}{\sqrt {-1-x^2}}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 39, normalized size = 1.26 \[ -\frac {i \sqrt {x^2+1} \operatorname {EllipticF}\left (i \sinh ^{-1}(x),-\frac {1}{2}\right )}{\sqrt {2} \sqrt {-x^2-1}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[-1 - x^2]*Sqrt[2 - x^2]),x]

[Out]

((-I)*Sqrt[1 + x^2]*EllipticF[I*ArcSinh[x], -1/2])/(Sqrt[2]*Sqrt[-1 - x^2])

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fricas [F]  time = 0.70, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {-x^{2} + 2} \sqrt {-x^{2} - 1}}{x^{4} - x^{2} - 2}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-1)^(1/2)/(-x^2+2)^(1/2),x, algorithm="fricas")

[Out]

integral(sqrt(-x^2 + 2)*sqrt(-x^2 - 1)/(x^4 - x^2 - 2), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-x^{2} + 2} \sqrt {-x^{2} - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-1)^(1/2)/(-x^2+2)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(-x^2 + 2)*sqrt(-x^2 - 1)), x)

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maple [A]  time = 0.03, size = 34, normalized size = 1.10 \[ \frac {i \sqrt {2}\, \sqrt {-x^{2}-1}\, \EllipticF \left (i x , \frac {i \sqrt {2}}{2}\right )}{2 \sqrt {x^{2}+1}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-x^2-1)^(1/2)/(-x^2+2)^(1/2),x)

[Out]

1/2*I*EllipticF(I*x,1/2*I*2^(1/2))/(x^2+1)^(1/2)*2^(1/2)*(-x^2-1)^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-x^{2} + 2} \sqrt {-x^{2} - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-1)^(1/2)/(-x^2+2)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(-x^2 + 2)*sqrt(-x^2 - 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {1}{\sqrt {-x^2-1}\,\sqrt {2-x^2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((- x^2 - 1)^(1/2)*(2 - x^2)^(1/2)),x)

[Out]

int(1/((- x^2 - 1)^(1/2)*(2 - x^2)^(1/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {2 - x^{2}} \sqrt {- x^{2} - 1}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x**2-1)**(1/2)/(-x**2+2)**(1/2),x)

[Out]

Integral(1/(sqrt(2 - x**2)*sqrt(-x**2 - 1)), x)

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